1) (3x - 2) - (x + 3) - 3x (x + 1) - 3 = 0; 2) (2x - вопрос №132331302222741350313626689 от Kononovichlika 30.06.2020 16:33

Question

Алгебра: 1) (3x - 2) - (x + 3) - 3x (x + 1) - 3 = 0; 2) (2x - 2) (2x + 7) - x (4x + 1) - 3,5 = 0;3) (2 - 5x). (2x - 1) + x (10x + 1) - 4,7 = 0;4) (2,4 - 5x). (4x - 1) + 2x (10x + 8,4) - 3,3 = 0;5) (x - 1) - x (x + 2)+ x (7x - 5) = 6;6) (2x - 1)3 - 2x² (4x - 6) + 10x - 5,4 = 0.​

Kononovichlika · Answer

(3х-2)-(х+3)-3х (х+1)-3=3х-3х=х 2+1=3 3+3=6 6+х=6х...

1) (3x - 2) - (x + 3) - 3x (x + 1) - 3 = 0; 2) (2x - 2) (2x + 7) - x (4x + 1) - 3,5 = 0;3) (2 - 5x). (2x - 1) + x (10x + 1) - 4,7 = 0;4) (2,4 - 5x). (4x - 1) + 2x (10x + 8,4) - 3,3 = 0;5) (x - 1) - x (x + 2)+ x (7x - 5) = 6;6) (2x - 1)3 - 2x² (4x - 6) + 10x - 5,4 = 0.​

1) (3x - 2) - (x + 3) - 3x (x + 1) - 3 = 0; 2) (2x - 2) (2x + 7) - x (4x + 1) - 3,5 = 0;
3) (2 - 5x). (2x - 1) + x (10x + 1) - 4,7 = 0;
4) (2,4 - 5x). (4x - 1) + 2x (10x + 8,4) - 3,3 = 0;
5) (x - 1) - x (x + 2)+ x (7x - 5) = 6;
6) (2x - 1)3 - 2x² (4x - 6) + 10x - 5,4 = 0.