1)(4m-2)2 4)(0,1t2-0,4k3)2 2)(8+5z)2 3)(1х+2y)2 - вопрос №14224012043228523122433458012 от ivansndreev1223 24.05.2023 21:32

Question

Алгебра: 1)(4m-2)2 4)(0,1t2-0,4k3)2 2)(8+5z)2 3)(1х+2y)2 - - 4 3

ivansndreev1223 · Answer

1) (4m - 2)^2 = (4m)^2 - 2 * 4m * 2 + 2^2 = 16m^2 - 16m + 4
2) (8 + 5z)^2 = 8^2 + 2 * 8 * 5z + (5z)^2 = 64 + 80z + 25z^2
3) (1/4x + 2/3y)^2 = (1/4x)^2 + 2 * 1/4x * 2/3y + (2/3y)^2 = 1/16x^2 + 1/3xy + 4/9y^2
4) (0,1t^2 - 0,4k^3)^2 = (0,1t^2)^2 - 2 * 0,1t^2 * 0,3t^3 + (0,4k^3)^2 = 0,01t^4 - 0,06t^5 + 0,16k9

квадрат суммы (a + b)^2 = a^2 + 2ab + b^2
квадрат разности (a - b)^2 = a^2 - 2ab + b^2