1. (a+6)(a+3)+(a-4)(a+5)2. 14x²(2x-3)(7x+4)=103. - вопрос №16345214237410350412531815434627 от idiotizROSSII 16.10.2020 20:12

Question

Алгебра: 1. (a+6)(a+3)+(a-4)(a+5)2. 14x²(2x-3)(7x+4)=103. x²-5x=04. (x+1)(x²-2x+5)+(x²+3)(1-x)=8​

idiotizROSSII · Answer

Объяснение:1. a^2+3a+6a+18+a^2+5a-4a-20=2a^2+10a-22.14x^2(14x^2+8x-21x-12)-10=196x^4-182x^3-168x^2-10=03.x(x-5)=0x=0; x=54.x^3-x^2+3x+5+x^2-x^3+3-x-8=2x...

1. (a+6)(a+3)+(a-4)(a+5)2. 14x²(2x-3)(7x+4)=103. x²-5x=04. (x+1)(x²-2x+5)+(x²+3)(1-x)=8​

1. (a+6)(a+3)+(a-4)(a+5)
2. 14x²(2x-3)(7x+4)=10
3. x²-5x=0
4. (x+1)(x²-2x+5)+(x²+3)(1-x)=8