1) (x-1)x(x+1)(x+2)=24 2) (x+4)(x+5)(x+7)(x+8)=4 - вопрос №111224245784312341208987020 от ZaraKerimova 22.04.2023 02:53

Question

Алгебра: 1) (x-1)x(x+1)(x+2)=24 2) (x+4)(x+5)(x+7)(x+8)=4 3) (x+1)(x+2)(x+3)(x+4)=120 это биквадратные

ZaraKerimova · Answer

(x + 1)(x + 2)(x + 3)(x + 4) = 120(x + 1)(x + 4)(x + 2)(x + 3) = 120(x² + 5x + 4)(x² + 5x + 6) = 120x² + 5x = a(a + 4)(a + 6) = 120a² + 10a + 24 = 120a² + 10a - 96 = 0a1 + a2 = -10a1a2 = -96a1 = -16a2 = 6x² + 5x = -16x² + 5x + 16 = 0x ∈ ∅x² + 5x = 6x² + 5x - 6 = 0x1 = -1x2 = 6...