(2х³)⁴*(-1/16ху²)=-(-а²b³)³*(-0,5a²b)²= - вопрос №21160514851100 от AndreyMiix 17.04.2021 20:04

Question

Алгебра: (2х³)⁴*(-1/16ху²)=-(-а²b³)³*(-0,5a²b)²=​

AndreyMiix · Answer

-(x¹¹/y²)0,25a¹⁰b¹¹Объяснение:(2х³)⁴(-1/ху²)=(2⁴(х³)⁴)(-1/16ху²)=(16х¹²)(-1/16ху²)=х¹¹/(-у²)=-(х¹¹/у²)-(-a²b³)³(-0,5a²b)²=-(-(a²)³(b³)³)((-0,5)²(a²)²b²)=-(-a⁶b⁹)(0,25a⁴b²)=0,25a¹⁰b¹¹...

(2х³)⁴*(-1/16ху²)=-(-а²b³)³*(-0,5a²b)²=​

(2х³)⁴(-1/16ху²)=
-(-а²b³)³(-0,5a²b)²=