(3 целых 5/18 - 7целых 1/12 + 2 целых 2/9) * (2,448 - вопрос №351871122292448124128659 от Annakuznetsova2006 22.04.2023 02:05

Question

Алгебра: (3 целых 5/18 - 7целых 1/12 + 2 целых 2/9) * (2,448 : 1,2)

Annakuznetsova2006 · Answer

Решение[3(5/18) - 7(1/12) + 2(2/9)] * (2,448 / 1,2) = [5(18/36) - 7(3/36)]  * (2,448 / 1,2) = [ - 1(21/36) ] * (2,04) = [ - 1(7/12)] * (1/25) = - (19/12) * (1/25)  = - 19*1/12*25 = - 19/300...