(3а³-а²+а)(-5а²) = (-2ах²+3ах-а²)(-а²х²) = (-0,5с⁴d)³(-4с²d²)²(-pq)⁶(6p²q)³(3mn)⁴(-3mn²)³ - вопрос №35230546337765086 от ярик467 29.03.2022 14:30

Question

Алгебра: (3а³-а²+а)(-5а²) = (-2ах²+3ах-а²)(-а²х²) = (-0,5с⁴d)³(-4с²d²)²(-pq)⁶(6p²q)³(3mn)⁴(-3mn²)³​

ярик467 · Answer

1) -15a^5+5a^4-5a^32)2a^3 x^4-3a^3 x^3+a^4 x^23) -2c^16 d^74) 216p^12 q^95) -2187^7 n^10...

(3а³-а²+а)(-5а²) = (-2ах²+3ах-а²)(-а²х²) = (-0,5с⁴d)³(-4с²d²)²(-pq)⁶(6p²q)³(3mn)⁴(-3mn²)³​