∫(9x+2)^17dx ∫3^(x+1) dx ∫-3dx/sin^2 x ∫(7x-1)^23 - вопрос №9217313271237231472 от polskryabina20 18.08.2022 10:46

Question

Алгебра: ∫(9x+2)^17dx ∫3^(x+1) dx ∫-3dx/sin^2 x ∫(7x-1)^23 dx

polskryabina20 · Answer

Решение∫(9x+2)^17dx = (1/9) * ∫(9x+2)^17d(9x+2) = (1/9)*[(9x+2)¹⁸ / 18] + C= (9x+2)¹⁸ / 162 + C∫3^(x+1) dx =  ∫3^(x+1)d(x+1)  = 3^(x+1) / ln3 + C∫-3dx/sin^2 x =  3*ctgx + C∫(7x-1)^23 dx =(1/7)* ∫(7x-1)^23 d(7x-1) = (1/7)*[(7x-1)²⁴]/24 + C == (7x-1)²⁴ / 168 + C...