А) x^2(x+2)-x(x+1)^2=5x+9 б)(y-3)^2+3(y+2)(y-2)=9+4y - вопрос №22125932322949042319 от mariaK918 26.04.2023 23:08

Question

Алгебра: А) x^2(x+2)-x(x+1)^2=5x+9 б)(y-3)^2+3(y+2)(y-2)=9+4y

mariaK918 · Answer

X²(x+2)-x(x+1)²=5x+9x³+2x²-x(x²-2x+1)=5x+9x³+2x²-x³+2x²-x=5x+94x²-x=5x+94x²-x-5x-9=04x²-6x-9=0x-(-6)+-√((-6)²-4*4(-9)) / 2*4x=6+-√(36+144) /8x=6+-√180 /8x=6+6√5 /8x=6-6√5 /8x=3+3√5/4x=3-3√5/4(y-3)²+3(y+2)(y-2)=9+4yy²-6y+9+3(y²-4)=9+4yy²-6y+9+3y²-12=9+4yy²-6y+3y²²-12=4y4y²-6y-12=4y4y²-6y-12-4y=04y²-10y-12=02y²-5y-6=0y-(-5)+-√((-5)²-4*2*(-6)) /2*2y=5+-√25+48 /4y=5+-√73 /4y=5+√73 /4y=5-√73 /4...