Докажите тождество sin(π/6+a)-cosa-cos(a-2π/3)=0 - вопрос №62305334290 от fairytale8 15.09.2021 22:23

Question

Алгебра: Докажите тождество sin(π/6+a)-cosa-cos(a-2π/3)=0

fairytale8 · Answer

sin(π/6+a)-cosa-cos(a-2π/3)=0sin(π/6+a)-cosa-cos(a-2π/3)==sin(π/6)cos(a)+sin(a)cos(π/6)-cosa-cos(a)cos(2π/3)-sin(a)sin(2π/3)==1/2cos(a)+sin(a)·(√3/2) - cosa - cos(a)·(-1/2)-sin(a)·(√3/2)=0...