Объяснение:
a) (2a+1)²/[(2a-1)²+8a] = 1
L=(2a+1)² / [2a-1)²+8a]= (4a²+4a+1) / (4a²-4a+1-8a)=
=(4a²+4a+1)/(4a²+4a+1=1 , P=1 i P=1 to L=P
b) (2a-1)²/[(2a+1)²-8a] = 1
L=(2a-1)² / [(2a+1)²-8a] = (4a²-4a+1) / (4a²+4a+1-8a] = =(4a²-4a+1)/(4a²-4a+1)= 1 ,P=1 i L=1 to L=P
Объяснение:
a) (2a+1)²/[(2a-1)²+8a] = 1
L=(2a+1)² / [2a-1)²+8a]= (4a²+4a+1) / (4a²-4a+1-8a)=
=(4a²+4a+1)/(4a²+4a+1=1 , P=1 i P=1 to L=P
b) (2a-1)²/[(2a+1)²-8a] = 1
L=(2a-1)² / [(2a+1)²-8a] = (4a²-4a+1) / (4a²+4a+1-8a] = =(4a²-4a+1)/(4a²-4a+1)= 1 ,P=1 i L=1 to L=P