)) log1/3 27√3, 3^1/2 log3 5, log4 log2 log3 81 - вопрос №1327331235423814711952 от leramoisejenko 27.05.2023 22:46

Question

Алгебра: )) log1/3 27√3, 3^1/2 log3 5, log4 log2 log3 81

leramoisejenko · Answer

log₁/₃ 27√3= - log₃ 3^(3,5) = - 3,53^(1/2 log₃ 5 )= 3^( log₃ √5)= √5log₄ log₂ log₃ 81 = log₄ log₂ log₃ 3⁴ =log₄ log₂ 4= log₄ log₂ 2²=log₄ 2= = log₂² 2= 1/2 log₂ 2 = 1/2...