S3: which kind of sports is your favourite? S1: Oh, I lobe hockey. I know everything about it. It's a winter sport, but simetimes people play it even when it's summer or autumn. S3: and you, S2? S2: well, I hate hockey. It's very dangerous to play in it, though sometimes games can be quite interesting. I love swimming. It's great to swim and relax in the same time. I love this feeling of relaxing and training [in the same time]. S1: oh, and you, S3? Which kind of sports do you prefer? S3: Frankly speaking, I like sport(s) but I didn't really know what I should choose. Can you help with that choice? S1: Yes, of course. Let's talk about it a bit later. S3+S2: Ok. See you then(,)guys. Bye.
Чтобы уравнение x² + 2(a+1)*x + 9 = 0 имело 2 разных положительных корня надо в общем виде : приведенное квадратное уравнение вида х² + b₁x + c₁= 0 имеет 2 положительных корня x₁ и x₂, если выполняются 3 условия 1) x₁*x₂ = c₁ > 0 - в нашем примере c₁ = 9 2) x₁+ x₂ = -b₁ > 0 - в нашем примере -b₁ = -(2(a+1)) -2a -2 > 0 ; a < -1 3) Дискриминант D = b₁² - 4c₁ > 0 - в нашем примере D = ( -(2(a+1)) )² - 4*9 D = (2a + 2 - 6) * (2a + 2 + 6) = (2a - 4) * (2a + 8) >0 (a - 2) * (a + 4) >0 корни -4 и 2, т.е. D>0 при а < -4 и a>2 пересечение множеств из 2) и 3) будет a < -4 Уравнение x² + 2(a+1)*x + 9 = 0 будет иметь два положительных корня при a < -4
S1: Oh, I lobe hockey. I know everything about it. It's a winter sport, but simetimes people play it even when it's summer or autumn.
S3: and you, S2?
S2: well, I hate hockey. It's very dangerous to play in it, though sometimes games can be quite interesting. I love swimming. It's great to swim and relax in the same time. I love this feeling of relaxing and training [in the same time].
S1: oh, and you, S3? Which kind of sports do you prefer?
S3: Frankly speaking, I like sport(s) but I didn't really know what I should choose. Can you help with that choice?
S1: Yes, of course. Let's talk about it a bit later.
S3+S2: Ok. See you then(,)guys. Bye.
приведенное квадратное уравнение вида х² + b₁x + c₁= 0 имеет 2 положительных корня x₁ и x₂, если выполняются 3 условия
1) x₁*x₂ = c₁ > 0 - в нашем примере c₁ = 9
2) x₁+ x₂ = -b₁ > 0 - в нашем примере -b₁ = -(2(a+1))
-2a -2 > 0 ; a < -1
3) Дискриминант D = b₁² - 4c₁ > 0 - в нашем примере D = ( -(2(a+1)) )² - 4*9
D = (2a + 2 - 6) * (2a + 2 + 6) = (2a - 4) * (2a + 8) >0
(a - 2) * (a + 4) >0 корни -4 и 2, т.е. D>0 при а < -4 и a>2
пересечение множеств из 2) и 3) будет a < -4
Уравнение x² + 2(a+1)*x + 9 = 0 будет иметь два положительных корня при a < -4