1) -4^(1/3)/x^2-1/3
(1/x)=-1/x^2
2) (x/cos^2x-tgx)/x^2=(x-0,5sin2x)/(x^2*cos^2x)
(tgx)=1/cos^2x
(f/g)'=(f'g-g'f)/g^2
3)sqrt(3)
Решение во вложении...!
1) -4^(1/3)/x^2-1/3
(1/x)=-1/x^2
2) (x/cos^2x-tgx)/x^2=(x-0,5sin2x)/(x^2*cos^2x)
(tgx)=1/cos^2x
(f/g)'=(f'g-g'f)/g^2
3)sqrt(3)
Решение во вложении...!