No 344 1)x*(x-4)+x-4=0, 2)y*(y+7)-4y-28=0 - вопрос №344144027428010736172 от tonuo84 30.12.2021 20:38

Question

Алгебра: No 344 1)x*(x-4)+x-4=0, 2)y*(y+7)-4y-28=0​

tonuo84 · Answer

1) x1 = 4, x2 = -1; 2) y1 = 4, y2 = -7Объяснение:1) x^2-4x+x-4 = 0x^2-3x-4 = 0по т.Виета:x1+x2 = 3x1*x2 = -4x1 = 4, x2 = -12) y^2+7y-4y-28 = 0y^2+3y-28 = 0y1+y2 = -3y1*y2 = -28y1 = 4, y2 = -7...

No 344 1)x*(x-4)+x-4=0, 2)y*(y+7)-4y-28=0​

No 344 1)x(x-4)+x-4=0, 2)y(y+7)-4y-28=0