k є Z
√20*sin5x + √5 = 0
√20*sin5x = - √5
sin5x = - √(5/20)
sin5x = - 1/2
5x = - pi/6 +2pik
x= - pi/30 + (2pik)/5, k∈Z
5x= 7pi/6 +2pik
x = 7pi/30 + (2pik)/5, k∈Z
- pi/30 + (2pik)/5, k∈Z
7pi/30 + (2pik)/5, k∈Z
k є Z
√20*sin5x + √5 = 0
√20*sin5x = - √5
sin5x = - √(5/20)
sin5x = - 1/2
5x = - pi/6 +2pik
x= - pi/30 + (2pik)/5, k∈Z
5x= 7pi/6 +2pik
x = 7pi/30 + (2pik)/5, k∈Z
- pi/30 + (2pik)/5, k∈Z
7pi/30 + (2pik)/5, k∈Z