Решите, : а²-4/3а+1 × (3а-1)(3а+1)/(3а²+5а-2) - вопрос №43131313529189617 от irichkagolikova 27.03.2022 01:33

Question

Алгебра: Решите, : а²-4/3а+1 × (3а-1)(3а+1)/(3а²+5а-2)

irichkagolikova · Answer

(à²-4)/(3a+1)*(3a-1)(3a+1)/(3a²+5a-2)=(a²-4)(3a-1)/(3a²+5a-2)3a²+5a-2=0D=25+24=49=7²a=(-5±7)/6a1=-2;a2=1/33a²+5a-2=3(a-1/3)(a+2)(a-2)(a+2)•1/3(a-1/3)/3(a+2)(a-1/3)=1/3(a-2):3==1/6(a-2)=(a-2)/6...