y=x^2+1y=2/xx^2+1=2/xx^3+x=2, x≠0x^3+x-2=0x^3-x+2x-2=0x(x^2-1)+2(x-1)=0x(x+1)(x-1)+2(x-1)=0(x-1)(x(x+1)+2)=0(x-1)(x^2+x+2)=0x=1; x^2+x+2=0 D=1-8=-7<0y=2/1=2ответ: (1;2)
y=x^2+1
y=2/x
x^2+1=2/x
x^3+x=2, x≠0
x^3+x-2=0
x^3-x+2x-2=0
x(x^2-1)+2(x-1)=0
x(x+1)(x-1)+2(x-1)=0
(x-1)(x(x+1)+2)=0
(x-1)(x^2+x+2)=0
x=1; x^2+x+2=0
D=1-8=-7<0
y=2/1=2
ответ: (1;2)