Решите я могу но спать хочу очень сильно. Алгебра, просто расписать с 1-6 задание ! можно сказать просто так

1) 3,2x-1,7x=1.5
1.5x=1.5
x=1

2) 2-0.9x+1.3=1.3x
3.3=1.3x+0.9x
2.2x=3.3
x=3.3/2.2
x=1.5

3) -3.3x-1.2-0.7x-1.6=0
-3.3x-0.7x=1.6+1.2
-4x=2.8
x=2.8/(-4)
x=-0.7

4) -4.1x-2.5-2.3x-3.9=1.6x
-4.1x-2.3x-1.6x=3.9+2.5
-8x=6.4
x=6.4/(-8)
x=-0.8

5) 3.6x+2.5-1.8x-2.3=1.6x
3.6x-1.8x-1.6x=2.3-2.5
0.2x=-0.2
x=-0.2/0.2
x=-1

6) 8.8x+4.7-5.4x-2.2=-1.6x
8.8x-5.4x+1.6x=2.2-4.7
5x=-2.5
x=-2.5/5
x=-0.5

7) 7.4x-12.3x-1.56+2.3x=2.6x
7.4x-12.3x+2.3x-2.6x=1.56
-5.2x=1.56
x=1.56/(-5.2)
x=-0.3

8) -2.9+8.2x-1.6+4.7x-2.9x=3.2
8.2x+4.7x-2.9x=3.2+2.9+1.6
10x=7.7
x=7.7/10
x=0.77

9) -4.1x+5.5x-7.3x-3.6=-5.3x
-4.1x+5.5x-7.3x+5.3x=3.6
-0.6x=3.6
x=3.6/(-0.6)
x=-6

10) 1.8x-1.9-2.7x+3.7=2.1x
1.8x-2.7x-2.1x=1.9-3.7
-3x=-1.8
x=(-1.8)/(-3)
x=0.6

1) y=2sin(4x)-8cos(x/4)+(1/2)*tg(2x)-(1/12)*ctg(6x)

    y ' =8cos(4x)+2sin(x/4)+1/cos^2(x)+sin^2(x)/2

 

2) y=sin(x/4)+12cos(x/3)-10tg(x/2)+5ctg(2x)

    y ' = cos(x/4)/4-sin(x/3)/3-5/cos^2(x/2)+2*sin^2(2x)/5

 

3) y=(8/12)*sin(3x/4)-(4/3)*cos(3x/4)-40ctg(x/5)-tg(8x)

    y ' = (1/2)*sin(3x/4)+sin(3x/4)+8/sin^2(x)-8/cos^2(x)

 

4) y =cos(2x)*x^5

    y ' =-2sin(2x)*x^5+5cos(2x)*x^4

5) y=sin(2x)/cos(4x)

    y ' =2cos(2x)/cos(4x)+4sin(2x)/cos^2(4x)

 

6) y=8cos(4x-pi/3)

   y ' =-32sin(4x-pi/3)

 

7) y=10x^5+7x^4-8x^3+4/x-9sqrt(x)-4x+1,1

    y ' = 50x^4+28x^3-24x^2-4/x^2-9/2*sqrt(x)-4

 

8) y=sin(3x)*tg(3x)

    y ' = 3cos(3x)*tg(3x)+sin(3x)*3/cos^2(3x)

 

9) y=5x^6+2x^3+6x^2-6x-8

    y ' = 30x^5+6x^2+12x-6

    y '' = 150x^4+12x+12

 

10) y=4sin(2x)-16cos(4/x)

      y ' = 8cos(2x)+64sin(x/4)/x^2

      y '' =-16sin(2x) +16cos(x/4)/x^2-128sin(x/4)/x^3