[tex](x + 4 {)}^{2} = 3x + 40[/tex][tex]3(x + 4 {)}^{2} - вопрос №4234034210321285787 от YourselfRuelfddd 26.04.2023 01:22

Question

Алгебра: [tex](x + 4 {)}^{2} = 3x + 40[/tex][tex]3(x + 4 {)}^{2} = 10x + 32[/tex]​

YourselfRuelfddd · Answer

( х + 4 )² = 3х + 40х² + 8х + 16 = 3х + 40х² + 8х + 16 - 3х - 40 = 0х² + 5х - 24 = 0D = 25 - 4 × 1 × (-24) = 121 0. 11.х1 = (-5 + 11) / 2 = 6/2 = 3.х2 = ( -5 - 11) / 2 = -16/2 = -8.Ответ : -8 ; 3.3 ( х + 4 )² = 10х + 323 ( х² + 8х + 16 ) = 10х + 323х² + 24х + 48 = 10х + 323х² + 24х + 48 - 10х - 32 = 03х² + 14х + 16 = 0D = 196 - 4 × 3 × 16 = 4 0. 2.х1 = ( -14 + 2 ) / 6 = -12/6 = -2.х2 = ( -14 - 2 ) / 6 = -16/6 = -8/3 = -2 ⅔.Ответ : -2 ; -2 ⅔.Удачи...

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$(x + 4 {)}^{2} = 3x + 40$ $3(x + 4 {)}^{2} = 10x + 32$