The set B = {1+t, 1+t², t+t²} is a basis for l₂ Find the
B-coordinate vector
of
1) P (t) = 6 +3t-t²
2) P (t) = 6-t+t²

Question

Алгебра: The set B = {1+t, 1+t², t+t²} is a basis for l₂ Find the B-coordinate vectorof1) P (t) = 6 +3t-t²2) P (t) = 6-t+t²​

Danatil · Answer

(a+b)*(a-b)                          a - b1)=    =           (a+b)*(a-b) - 8*(a+b)         a - b - 8        x² - y² -4x + 4y       (x+y)*(x-y) - 4*(x-y)         x + y - 42)= = =          (x+y)*(x-y)             (x+y)*(x-y)                      x + y        (b - 1)² - c²                         (b - 1 + c)*(b - 1 - c)      b - c - 13) = = =         (b + c)*(b - c) - (b - c)         (b - c)*(b + c -1)            b - c        10² - (x² - 2xy +y²)                    10² - (x - y)²4) =  =...

The set B = {1+t, 1+t², t+t²} is a basis for l₂ Find the B-coordinate vectorof1) P (t) = 6 +3t-t²2) P (t) = 6-t+t²​

The set B = {1+t, 1+t², t+t²} is a basis for l₂ Find the
B-coordinate vector
of
1) P (t) = 6 +3t-t²
2) P (t) = 6-t+t²