Выражения 1) 0,512t^3-100+(0.8t+5)(0.64t^2-4t+25) - вопрос №10512310008506424252113121211361338661770 от leragoroshkova 03.02.2020 08:09

Question

Алгебра: Выражения 1) 0,512t^3-100+(0.8t+5)(0.64t^2-4t+25) 2) (1.1d-c^3)(1.21d^2+1.1c^3d+c^6)-1.331d^3+2c^9

leragoroshkova · Answer

0,512t³ - 100 + (0,8t + 5)(0,64t² - 4t + 25 ) = 0,512t³ - 100 + 0,512t³ + 125 = 25(1,1d - c³)(1,21d² + 1,1c³d + c⁶) - 1,331d³ + 2c⁹ =1,331d³ - c⁹ - 1,331d³ + 2c⁹ =c⁹...