Заранее ! log по осн.x 2-log по осн.4 x+7/6=0 - вопрос №247603134723 от yuliaspavlovitc 07.01.2022 18:03

Question

Алгебра: Заранее ! log по осн.x 2-log по осн.4 x+7/6=0

yuliaspavlovitc · Answer

Log(x)2-log(4)x+7/6=01/log(2)x -1/2*log(2)x+7/6=06-3(log(2)x)²+7log(2)x=0  log(2)x≠0log(2)x=a3a²-7a-6=0D=49+72=121a1=(7-11)/6=-2/3⇒log(2)x=-2/3⇒x=1/∛4a2=(7+11)/6=3⇒log(2)x=3⇒x=8...