podstavliaem vmesto y=x-2 poluchae, x-2=x^2+x-3 perenosim v pravuiu chasti poluchaem x^2-1=0 x^2=1 x=+-1 znachit esli x=1 y=-1, x=-1 y=-3
вложение.........................................................
podstavliaem vmesto y=x-2 poluchae, x-2=x^2+x-3 perenosim v pravuiu chasti poluchaem x^2-1=0 x^2=1 x=+-1 znachit esli x=1 y=-1, x=-1 y=-3
вложение.........................................................