Complete the table and the rules below. I've cut my fingers a few times, and I've burnt
my hand with boiling water
He fell off a chair last week.
We use the to say when something happened.
We use words like last week, yesterday, two weeks ago.
We use the if we don't know when something
happened or it's not important when something
happened. We use words like ever, never, in the last ten
years, in my life, etc.

I.GRAMMAR: 
Example: She a student. She’s a teacher.
 B isn’t 
1 We to France last summer.
 C went
2 I always toast for breakfast.
 B have 
3 your brother play the guitar?
A Does 
4 My mum doesn’t like to work.
 B driving 
5 They TV at the moment.
A ’re watching 
6 I to Rome.
 B ’ve never been 
7 What tomorrow afternoon?
 B are you going to do 
8 We to Rome and then we drove to Florence.
A flew 
9 She to school today because she’s ill.
A doesn’t go 
10 I at the moment because I’m on holiday.
A ’m not studying 
11 Have you ever Japanese food?
 B eaten 
12 They pizza. They had pasta.
A didn’t have 
13 Who your favourite actors?
 B are
14 How often to the cinema?
B do you go 
15 They early on Sundays.
 C don’t get up
16 This is interesting book. Have you read it?
 B an 
17 I often go shopping the weekend.
 C at
18 The children played in the garden.
 C happily
19 These shoes aren’t . Look! They’re too small.
C mine
20 there any biscuits?
A Are 
21 She hardly travels abroad.
 B ever 
22 Paul left work an hour .
 C ago
23 How chocolate do you eat?
 B much 
24 This is film I’ve ever seen.
A the best 
25 I’m younger my sister.
B than 

Сначала формулы . затем формулы двойного угла sin2α=2sinαcosα cos2α=cos²α-sin²α=cos²α-(1-cos²α)=2cos²α-1⇒  2cos²α=1+cos2α cos2α=cos²α-sin²α=1-sin²α-sin²α=1-2sin²α⇒  2sin²α=1-cos2α а) сos75°cos105°=cos(90°-15°)·cos(90°+15°)== sin15°(-sin15°)=-sin²15°=-(1-cos30°)/2=(cos30°-1)/2= ((√3/2)-1)/2=0,25√3-0,5б) sin75°sin15°=°sin(90°-15°)sin15°=cos15° sin15°=sin30°/2=1/4=0,25в) sin105°cos15°=sin(180°-75°)cos15°=sin75°cos15°=sin(90°-15°)cos15°=cos15°cos15°=(1+cos30°)/2=(1+(√3/2))/2=0,5 +0,25√3 2 способ формулы cosα·cosβ=0,5cos(α-β)+0,5cos(α+β) sinα·sinβ=0,5cos(α-β)-0,5cos(α+β) sinα·cosβ=0,5sin(α+β)+0,5sin(α-β) а) сos75°cos105°=0,5cos(75°-105°)+0,5cos(75°+105°)=0,5cos(-30°)+0,5 cos180°==0,5· √3/2+0,5·(-1)=0,25√3-0,5б) sin75°sin15°=0,5cos(75°-15°)-0,5cos(75°+15° )=0,5cos60°-0,5 cos90°=0,5·0,5=0,25в) sin105°cos15°=0,5sin(105°+15°)+0,5sin(105°-15°)= =0,5sin120°+0,5sin90°==0,5 sin(180°-60°)+0,5·1=0,5 sin 60°+0,5=0,25√3+0,5