1)Укажите формулу для нахождения энергии кванта при поглощении ядром △M = Zmp+Nmn - Mя
E = △Mc²
hʋ = Е₂ - E₃
E = △Mc²/А
2)Укажите формулу для нахождения удельной энергии связи
△M = Zmp+Nmn - Mя
E = △Mc²
hʋ = Е₂ - E₃
E = △Mc²/А
2)Укажите число нейтронов в атоме
9
4
13
5
3)Укажите число электронов в атоме бария
137
56
81
193
4)Укажите число нуклонов в атоме железа
56
26
30
82
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R2=U²/P=220²/60=48400/60=807 Ом - сопротивление 2 лампы
лампы будут включены последовательно, значит общее сопротивление цепи равно R=R1+R2=1210+807= 2017 Ом сопротивление всей цепи, в последовательной цепи ток одинаковый значит I=U/R=220/2017=0.11 А, зная ток и сопротивление находим мощность каждой лампы P=I*U если I=U/R то U=I*R подставим в выражение P=I*I*R1=I²*R1= 0.0121*1210 =14.64 Вт - первая лампа
P=I*I*R2=I²*R2= 0.0121*807=9.76 вторая лампа
проверяем
U1=I*R1= 0.11*1210=133.1 Вольт - напряжение на первой лампе U2=I*R2=0.11*807=88.7 - напряжение на второй лампе ( в последовательной цепи общее напряжение равно сумме напряжений на каждом сопротивлении ) P1=I*U1=0.11*133.1=14.64 Вт - 1 лампа, P2=I*U2=0.11*88.7=9.76 Вт -2 лампа