3.16
Объяснение:
a = {3; -2} , b = {4; 1} c=?
===
x1=3 y1=-2 x2=4 y2=1
c=√((x2-x1)²+(y2-y1)²)=√((4-3)²+(1+2)²)=√10≈3.16
3.16
Объяснение:
a = {3; -2} , b = {4; 1} c=?
===
x1=3 y1=-2 x2=4 y2=1
c=√((x2-x1)²+(y2-y1)²)=√((4-3)²+(1+2)²)=√10≈3.16