Как известно, источник тока совершает работу как во внешней цепи так и во внутренней. Можно ли считать постоянной работу, совершаемую им во внешней цепи? Во внутренней цепи?
2) подвижный блок дает выигрыш в силе в два раза, так как передвигается вместе с грузом что сокращает путь в 2 раза. а так как путь и сила прямо пропорциональны при уменьшении пути , прикладываемая сила тоже уменьшается
3) F1*L1 равно F2*L2
из этого F2 равно F1*L1/L2
получается 50Н*L/2L. сокращаем L и выходит 50Н/2, получается F2 равно 25Н
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Объяснение:
1)2кНм- 2000 Н/м
500 мг-0,0005 кг
0,003 МДж- 3000 Дж
0,2 кВт- 200 Вт
2) подвижный блок дает выигрыш в силе в два раза, так как передвигается вместе с грузом что сокращает путь в 2 раза. а так как путь и сила прямо пропорциональны при уменьшении пути , прикладываемая сила тоже уменьшается
3) F1*L1 равно F2*L2
из этого F2 равно F1*L1/L2
получается 50Н*L/2L. сокращаем L и выходит 50Н/2, получается F2 равно 25Н
4) кинетическая энергия равна mV в квадрате/2
подставляем цифры получается 70*400/2 равно 14кДж
5) N равно A/t из этого, t равно A/N
получается 2400Н*5000м/50000 Вт равно 240с
6)формула КПД равна η=Ap/Apoln⋅100%
из этого Ар равна 24кг*10Н/кг*5м равно 1200 Дж
Ароln равна 150Н*10м равно 1500 Дж
потом 1200Дж/1500Дж и умножаем на 100%
получается 80%