Кусок пластилина упал с третьего этажа. Его масса равна 50\ г50 г, удельная теплоёмкость пластилина — 2{,}5 \frac{кДж}{кг \cdot ^{\circ}С}2,5 кг⋅ ∘ С кДж , 11 этаж =3\ м=3 м. Считая, что вся кинетическая энергия во время удара перешла во внутреннюю, определи, на сколько градусов нагрелся кусок пластилина. Запиши ответ числом.

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Ответ:

впапорпорпрорп

03.10.2020 15:10

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Ответ:

TheDorams

08.06.2021 14:40

60 °С

Объяснение:

Основная формула теплоемкости: Q = M*С*T, где Q - количество теплоты, М - масса, Т - температура, С - теплоемкость. (Вообще, пишут ΔТ, но, в нашей задаче можно считать ΔТ = Т - количество теплоты относительно 0°С. )

Масса кофе после доливания воды составляет

Mкофе = Мокофе+ Мводы = 60+20 = 80 г.

Количество теплоты кофе Qкофе после доливания воды составляет

Qкофе = Mкофе*Скофе*Tкофе (1)

Количество теплоты воды Qводы составляет:

Qводы = Mводы*Своды*Tводы (2)

Количество теплоты кофе, до того как в него налили воды составляет:

Qокофе = Mокофе*Скофе*Tокофе (3),

таким образом получаем:

Qкофе = Qокофе + Qводы (4)

Подставляя d (4) выражения для Q из формул (1),(2),(3) получаем:

Mкофе*Скофе*Tкофе = Mокофе*Скофе*Tокофе + Mводы*Своды*Tводы