Дано:
t1 = -10oC T1 = 263K
t2 = 10oC T2 = 283K
E - ?
∆Е = 3/2 *k∆T
∆Е = 3/2 *1.38*10^-23*20 = 4.14*10^-22 Дж
Дано:
t1 = -10oC T1 = 263K
t2 = 10oC T2 = 283K
E - ?
∆Е = 3/2 *k∆T
∆Е = 3/2 *1.38*10^-23*20 = 4.14*10^-22 Дж