С дано К 1 м 3 воды при температуре 20 ° С добавили 160 ° С горячей воды, после чего температура смеси стала 80 ° С. Сколько составляет объем горячей воды?

Решение. m=(h*c)/(L*c^2); m=h/(c*L);                                                              h-6,625*10^-34;                                                                                                  c=3*10^8;                                                                                                           L=0,7*10^-7;                                                                                                            m =6,625*10^-34/ 3*10^8*0,7*10-7=31,5*10^-34 ;                                                                                   ^- озночает в степени

Решение. m=(h*c)/(L*c^2); m=h/(c*L);                                                              h-6,625*10^-34;                                                                                                  c=3*10^8;                                                                                                           L=0,7*10^-7;                                                                                                            m =6,625*10^-34/ 3*10^8*0,7*10-7=31,5*10^-34 ;                                                                                   ^- озночает в степени