1. Sally was 18 when she became one of the best young tennis players in the USA.
2. Literature - is one of Sally Ride’s favorite subjects.
3. Sally was engaged in learning astrophysics in college.
4. She was a specialist in astrophysics.
5. She learned to control military jets as part of her training in Houston.
6. Sally spent six day in space flying around the earth.
Объяснение:
She was ranked number eighteen among the best young tennis players in the country when she was 18."-1 вопрос,получается ответ вместо пропуска 18
"She liked great literature too."-2 вопрос ответ literature
When she went to college, she studied astrophysics." - 3 вопрос,ответ "college"
She was a specialist in astrophysics." - ответ на 4 вопрос "astrophysics"
She studied at the Johnson Space Center in Houston, Texas. She learnedhow to fly military jets as part of her training."- ответ на 5 вопрос "military jets as part of her training"
Sally ride spent six days in space orbiting the earth"- значит ответ "six"
1. Sally was 18 when she became one of the best young tennis players in the USA.
2. Literature - is one of Sally Ride’s favorite subjects.
3. Sally was engaged in learning astrophysics in college.
4. She was a specialist in astrophysics.
5. She learned to control military jets as part of her training in Houston.
6. Sally spent six day in space flying around the earth.
Объяснение:
She was ranked number eighteen among the best young tennis players in the country when she was 18."-1 вопрос,получается ответ вместо пропуска 18
"She liked great literature too."-2 вопрос ответ literature
When she went to college, she studied astrophysics." - 3 вопрос,ответ "college"
She was a specialist in astrophysics." - ответ на 4 вопрос "astrophysics"
She studied at the Johnson Space Center in Houston, Texas. She learnedhow to fly military jets as part of her training."- ответ на 5 вопрос "military jets as part of her training"
Sally ride spent six days in space orbiting the earth"- значит ответ "six"
Виктория, задача решается так:
Дано:
Е = 200 В/м
а = 0,5 м
ε0 = 8,85•10*-12 Ф/м
Найти τ
Е = Q / 4•π•ε0•r*2 где: r - расстояние от заряда до точки наблюдения.
Q = τ•L тогда:
Е = τ•L / 4•π•ε0•r*2
Т. к. заряд Q несёт вся проволока, длину которой будем считать бесконечной, то элемент длины dL будет создавать элементарный заряд dE:
dE = [τ / 4•π•ε0•(a/cosα)*2]•dL (1)
dL = (a/cosα)•dα (2)
Подстаавим (2) в (1):
E = 2•∫[от 0 до π/2] [τ / 4•π•ε0•(a/cosα)*2]•(a/cosα)•dα (3) - в силу симметрии берётся удвоенный интеграл [от 0 до π/2], а не от [от -π/2 до π/2].
Преобразуем (3):
E = ∫[от 0 до π/2] [τ / 2•π•ε0•a]•cosα•dα = [τ / 2•π•ε0•a]• ∫[от 0 до π/2]cosα•dα
E = [τ / 2•π•ε0•a]• sinα [от 0 до π/2] = τ / 2•π•ε0•a
Откуда:
τ = 2•π•ε0•a•E
Вычислим:
τ = 2•3,14•8,85•10*-12 Ф/м • 0.5 м • 200 В/м = 5,6•10*-9 Кл/м - ответ.