c-лід
С-вода
Q=cm(0-(-10))+λm+Cm(100-0)+Lm=m(10c+λ+L+100C)=m*10^3(21+335+2300+420)=
=2*10^3*3076=6152кДж
c-лід
С-вода
Q=cm(0-(-10))+λm+Cm(100-0)+Lm=m(10c+λ+L+100C)=m*10^3(21+335+2300+420)=
=2*10^3*3076=6152кДж