Решите : )
№1

в прямоугольном треугольнике авс ав — гипотенуза, сн — медиана. точка о лежит на середине сн. найдите площадь овс, если вс = 8, ас = 6

№2

в прямоугольной трапеции меньшая боковая сторона равна 4 и составляет с меньшей диагональю угол, равный 45°. острый угол трапеции равен 45°. найдите площадь трапеции

I love autumn holidays. They give a breather in their studies. I just wish they were so short. Autumn holidays last only a week, sometimes ten days. You do not have time to relax properly, as it is time to go to school. But quickly you can not get up early in the morning. And then you barely get out of bed in the morning. Usually I spend autumn vacation at home. The weather is already cold and rainy, so you do not go out on the street especially. At home, I read books, or I dig on the Internet. If the sun looks out, I go out into the yard. In the evenings, we play with checkers, backgammon and other board games. Sometimes, when the weather permits, parents go to the forest for mushrooms. And I, of course, are also taken with me. Therefore, with the word "autumn vacation", I first of all recall the wet forest and mushrooms. Even on the autumn holidays, we go to my grandmother. I stay with her for a few days. By my arrival, my grandmother usually takes tickets to the circus or to a children's play, and we go with her to watch the performance. So that we are not bored on vacation, our class teacher also organizes a cultural campaign, for example, in a museum or an exhibition. During the last autumn holidays we visited the dolphinarium. There were trained sea fur seals, white whales and dolphins. I still have a lot of impressions! So those autumn holidays I spent very well.

Боковые стороны равны 10 см, основание равно 8 см.

Объяснение:

Дан равнобедренный  треугольник АВС с основанием АС. По условию точка касания делит боковые сторону  (они равны) на отрезки x и y, считая от вершины В.

Касательные к вписанной окружности , проведенные из одной вершины, равны. Следовательно, периметр треугольника равен:

Рabc = 2x +4y = 28 см. (1)  (уравнение)

x - y =2 (дано)  => y = x-2. Подставляем это значение в (1):

2x + 4x - 8 = 28  => x = 6 см.   y = 4 см.  =>

Боковые стороны равны x+y = 10 см, основание равно 2y = 8 см.