Точка X делит сторону BF в отношении BX : XF = 4 : 3, точка Y делит сторону FA в отношении Fү : YA = 4: 3. Разложи вектор XY по векторам ХҮ по векторам FB и FA:
Speaking Task 1. Choose the question from the card on the topic Entertainment and fedia^ prime prime and be ready to answer it after the teacher starts the conversation. Produce a speech by giving extended answers to the questions. Share your ideas with the class. Teacher organizes a Socratic seminar, which helps him/her to assess learners while they are speaking on the toplic Entertainment and Media and he/she prepares and cuts down questions and expressions beforehand. Learners sit in a circle and answer the question using in their speech some formal and Informal expressions to present logically connected information to their classmates. Expressions: Stating an opinion The way I see it... Sorry to interrupt, but... Is it okay if I jump in for a second? Can I add something here? Can I throw my two cents in? Not necessarily Interrupting If I might add something..... I beg to differ No, I'm not so sure about that That's for sure Expressing disagreement I'd say the exact opposite I have to side with somebody (name)on this one I was just going to say that In my opinion Expressing agreement If you ask me.. That's exactly how I feel As far as I'm concerned. If you want my honest opinion..... You have a point there That's not always the case
S=πRl+πR², ( l образующая)
Sполн.пов.=πR*(l+R)
1. сечение конуса - равнобедренный прямоугольный треугольник: гипотенуза - хорда х=6, катеты - образующие конуса l.
по теореме Пифагора:
x²=l²+l², 6²=l²+l², l²=18, l=3√2
2. осевое сечение конуса - равнобедренный треугольник основание - диаметр основания конуса d, боковые стороны - образующие конуса l.
по теореме косинусов: d²=l²+l²-2*l*l*cos120°
d²=18+18-2*√18*√18*(-1/2)
d²=54, d=3√6. R=1,5√6
S=π*1,5(√6*3√2+1,5)=1,5*π*(6√2+1,5)
S=1,5π*(6√2+1,5)