По теореме синусов
BC/ sinA = AC/ sinB
BC/sin60 = 6/sin45
BC/√3/2 = 6/√2/2
2BC/√3=12/√2
BC/√3=6√2
BC=6√3/√2= 6√3*√2/√2*√2 = 6√6/2 = 3√6
По теореме синусов
BC/ sinA = AC/ sinB
BC/sin60 = 6/sin45
BC/√3/2 = 6/√2/2
2BC/√3=12/√2
BC/√3=6√2
BC=6√3/√2= 6√3*√2/√2*√2 = 6√6/2 = 3√6