BC=ABSinA=AB√1-Cos²A=AB√1-(1/(1+tg²A)=5√1-(1/1+49/576)=5√1-(576/625)=5√49/625=5*(7/25)=7/5= 1.4
по т. Пифагора:
AC=√AB²-BC²=√25-1.96=√23.04=4.8
BC=ABSinA=AB√1-Cos²A=AB√1-(1/(1+tg²A)=5√1-(1/1+49/576)=5√1-(576/625)=5√49/625=5*(7/25)=7/5= 1.4
по т. Пифагора:
AC=√AB²-BC²=√25-1.96=√23.04=4.8