Выражение: 1)1-sin^2a= 2)1+sin^2a+cos^2a= 3)(1-cosa)(1+cosa)= - вопрос №1122122311426859022 от likairin00Lika123 25.06.2021 06:06

Question

Геометрия: Выражение: 1)1-sin^2a= 2)1+sin^2a+cos^2a= 3)(1-cosa)(1+cosa)= 4)sina-sina*cos^2a=sina*( )= 5)sin^4a+2sin^2a*cos^2a+cos^4a= 6)tg^2a-sin^2a*tg^2a= 7)cos^2a+cos^2a*tg^2a= 8)tg& 2a*(2cos^2a+sin^2a-1)=

likairin00Lika123 · Answer

1) 1-sin^2a= cos^2a2) 1+sin^2a+cos^2a = 23) (1-cosa) (1+cosa) = 1-cos^2a = sin^2a4) sina - sina*cos^2a= sina(1-cos^2a) = sin^3a5) sin^4 + 2sin^2a*cos^2a + cos^4a = (sin^2a+cos^2a) ^2= 16) tg^2a-sin^2a*tg^2a = tg^2a (1-sin^2a) = sin^2a/cos^2a * cos^2a = sin^2a7) cos^2a + cos^2a*tg^2a = cos^2a + cos^2a*sin^2a/cos^2a = cos^2a + sin^2a = 18) tg^2a ( 2cos^2a + sin^2a- 1) = tg^2a*(2cos^2a-cos^2a) = sin^2a/cos^2a * cos^2a = sin^2a...