function DifNum(a: integer): integer; var se: set of integer; i: integer; begin while a > 0 do begin if a mod 10 in se then begin DifNum := 0; exit; end else include(se, a mod 10); a := a div 10; end; DifNum := 1; end;
begin read(l, r); for i := l to r do counter += DifNum(i); writeln(counter); end.
//Альтернативное решение на Паскале
Var l,r:integer; begin read(l,r); writeln(range(l,r).where(x -> x.tostring.toarray.distinct.count=length(x.tostring)).Count); end.
#include <iostream>
#include <cmath>
using namespace std;
signed main()
{
setlocale(LC_ALL, "Rus");
int N;
bool haveZero = false, haveOne = false;
cin >> N;
N = abs(N);
while(N>0){
if(N % 10 == 0)
haveZero = true;
if(N % 10 == 1)
haveOne = true;
N /= 10;
}
cout << "Наличие нуля: " << boolalpha << haveZero << endl;
cout << "Наличие единицы в числе: " << boolalpha << haveOne << endl;
return 0;
}
var
l, r, counter, i: integer;
function DifNum(a: integer): integer;
var se: set of integer;
i: integer;
begin
while a > 0 do
begin
if a mod 10 in se then
begin
DifNum := 0;
exit;
end
else include(se, a mod 10);
a := a div 10;
end;
DifNum := 1;
end;
begin
read(l, r);
for i := l to r do
counter += DifNum(i);
writeln(counter);
end.
//Альтернативное решение на Паскале
Var
l,r:integer;
begin
read(l,r);
writeln(range(l,r).where(x -> x.tostring.toarray.distinct.count=length(x.tostring)).Count);
end.
//Dev-C++ 5.11 (C)
#include <stdio.h>
#include <malloc.h>
int DifNum(int);
int main(void)
{int l,r,counter=0;
scanf("%d %d",&l,&r);
for(int i=l;i<=r;i++)
counter+=DifNum(i);
printf("%d",counter);
return 0;}
int DifNum(int a)
{int k=1,*nums;
nums=(int*)malloc(k*sizeof(int));
nums[0]=-1;
while(a>0)
{for(int i=0;i<k;i++)
if(a%10==nums[i])
return 0;
k++;
nums=(int*)malloc(k*sizeof(int));
nums[k-1]=a%10;
a/=10;}
free(nums);
return 1;}
Пример ввода:
1 12
Пример вывода:
11