1. У яких вказівках повторення збільшення (зменшення) лічильника циклу на 1 передбачено:

1) автоматично;

2) програмістом?

a) while..do;

б) for..to..do;

в) repeat..until.

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Так как целевой ЯП не указан, приведу пример на Haskell.

Точка входа - функция main.

Main.hsmodule Main whereimport ArrsMinmain :: IO ()main = dialogArrsMin.hsmodule ArrsMin whereimport System.IO(hFlush, stdout)import Data.Char(isDigit)import Data.Maybe(isJust)import Control.Applicativeimport Numeric(showHex)import MyParserLibparserInt :: Parser IntparserInt = Parser (\s -> let res = unParser (some digitParser) s in case res of        [] -> []        ((i, rest) : _) -> [(read i :: Int, rest)]    ) where        digitParser = predP isDigitparserIntSequence :: Parser [Int]parserIntSequence = Parser (\s -> let res = unParser (some elementParser) s in case res of        [] -> []        ((i, rest) : _) -> [(i, rest)]    ) where        elementParser = (<*) parserInt $ many $ charP ' 'intToHex :: Int -> StringintToHex = flip showHex ""isItCorrect :: String -> BoolisItCorrect s | (length s == 2) && (head s > s !! 1) = True              | otherwise                            = FalsetakeOnlyCorrect :: Maybe [Int] -> Maybe [Int]takeOnlyCorrect = fmap $ filter (isItCorrect . intToHex)minimum' :: (Ord a) => Maybe [a] -> Maybe aminimum' Nothing = Nothingminimum' (Just []) = Nothingminimum' (Just a) = Just (minimum a)unJust :: Maybe a -> IO aunJust (Just a) = return aunJust Nothing = fail "You can't unjust Nothing"dialog :: IO ()dialog = do    putStr "Put your int sequence: "    hFlush stdout    stupidUserInput <- getLine    let sequen = parseString stupidUserInput parserIntSequence    let answer = minimum' $ takeOnlyCorrect sequen    if isJust answer        then do            number <- unJust answer            print number        else            putStrLn "0"MyParserLibmodule MyParserLib whereimport Data.Listimport Control.Applicativetype DataText = Stringtype RestText = Stringtype PResults parsedType = [(parsedType, RestText)]newtype Parser parsedType = Parser {unParser :: DataText -> PResults parsedType}instance Functor Parser where  fmap f (Parser p1) = Parser p2    where      p2 s = convert (p1 s)      convert  = map (\(val, s) -> (f val, s))instance Applicative Parser where    pure x = Parser (\str -> [(x, str)])    pf <*> px = Parser (\str -> [(f x, sx) | (f, sf) <- unParser pf str,                                             (x, sx) <- unParser px sf])instance Alternative Parser where    empty = Parser (const [])    px <|> py = Parser (\s -> unParser px s ++ unParser py s)parseString :: String -> Parser a -> Maybe aparseString str (Parser p) = case p str of    [(val, "")] -> Just val    _           -> NothingpredP :: (Char -> Bool) -> Parser CharpredP p = Parser f    where        f "" = []        f (c:cs) | p c = [(c, cs)]                 | otherwise = []charP :: Char -> Parser CharcharP ch = predP (\c -> c == ch)stringP :: String -> Parser StringstringP str = Parser    f    where        f str' | str == str' = [("", str)]               | otherwise = [] skip :: (Char -> Bool) -> Parser ()skip p = Parser (\str -> [((), dropWhile p str)])prefixP :: String -> Parser StringprefixP token = Parser f    where        f str | token `isPrefixOf` str = [(drop (length token) str, token)]              | otherwise = []skipString :: String -> Parser ()skipString token = () <$ prefixP token

Код#include <iostream>#include <cmath>void first_task() {    std::cout << "Frist task!" << std::endl;    double A;    std::cout << "Enter A: ";    std::cin >> A;    std::cout << "The answer is " << (1200 - A) / A << std::endl;    std::cout << std::endl;}void second_task() {    std::cout << "Frist task!" << std::endl;    int A, B, C;    std::cout << "Enter A: ";    std::cin >> A;    std::cout << "Enter B: ";    std::cin >> B;    std::cout << "Enter C: ";    std::cin >> C;    double P = A + B + C, p = P / 2;    std::cout << "P = " << P << std::endl;    std::cout << "S = " << std::sqrt(p*(p-A)*(p-B)*(p-C)) << std::endl;    std::cout << std::endl;}void third_task() {    std::cout << "Third task!" << std::endl;    int n;    std::cout << "Enter your number: ";    std::cin >> n;    std::cout << "Your number is " << n << std:: endl;    std::cout << "In oct: " << std::oct << n << std:: endl;    std::cout << "In hex: " << std::hex << n << std:: endl;    std::cout << std::endl;}int main() {    first_task();    second_task();    third_task();    return 0;}