12. Приведите пример алгоритма, работающего бесконечно: а) при некоторых исходных данных: Место для ввода текста. при исходных данных: место для вода: б) при любых исходных данных: Место для ввода текста.
Var a1,a2,a3,a4,a5,a6,a7,a8,k:integer; begin k:=0; read (a1,a2,a3,a4,a5,a6,a7,a8); if (a1>0) and (a2>0) and (a3>0) and (a4>0) and (a5>0) and (a6>0) and (a7>0) and (a8>0) then begin if (a1 mod 3 = 0) and (a1 mod 10 = 4) then k:=k+1; if (a2 mod 3 = 0) and (a2 mod 10 = 4) then k:=k+1; if (a3 mod 3 = 0) and (a3 mod 10 = 4) then k:=k+1; if (a4 mod 3 = 0) and (a4 mod 10 = 4) then k:=k+1; if (a5 mod 3 = 0) and (a5 mod 10 = 4) then k:=k+1; if (a6 mod 3 = 0) and (a6 mod 10 = 4) then k:=k+1; if (a7 mod 3 = 0) and (a7 mod 10 = 4) then k:=k+1; if (a8 mod 3 = 0) and (a8 mod 10 = 4) then k:=k+1; writeln (k); end else writeln ('Неверный ввод'); end.
begin
k:=0;
read (a1,a2,a3,a4,a5,a6,a7,a8);
if (a1>0) and (a2>0) and (a3>0) and (a4>0) and (a5>0) and (a6>0) and (a7>0) and (a8>0) then
begin
if (a1 mod 3 = 0) and (a1 mod 10 = 4) then k:=k+1;
if (a2 mod 3 = 0) and (a2 mod 10 = 4) then k:=k+1;
if (a3 mod 3 = 0) and (a3 mod 10 = 4) then k:=k+1;
if (a4 mod 3 = 0) and (a4 mod 10 = 4) then k:=k+1;
if (a5 mod 3 = 0) and (a5 mod 10 = 4) then k:=k+1;
if (a6 mod 3 = 0) and (a6 mod 10 = 4) then k:=k+1;
if (a7 mod 3 = 0) and (a7 mod 10 = 4) then k:=k+1;
if (a8 mod 3 = 0) and (a8 mod 10 = 4) then k:=k+1;
writeln (k);
end else
writeln ('Неверный ввод');
end.
#include <iostream>
using namespace std;
int main()
{
int sum = 0;
int composition = 1;
bool plusSeq = 1;
int n = 0;
cout << "Size array - ";
cin >> n;
int* a = new int[n];
for (int i = 0; i < n; i++)
{
a[i] = -10 + rand() % 21;
sum += a[i];
composition *= a[i];
cout << a[i] << " ";
}
for (int i = 0; i < n; i++)
{
if (a[i] < 0)
a[i] *= a[i];
}
for (int i = 1; i < n; i++)
{
if (a[i] < a[i - 1])
{
plusSeq = 0;
break;
}
}
if (plusSeq)
cout << "\nSum = " << sum;
else
cout << "\nComposition = " << composition;
delete[]a;
return 0;
}
Объяснение: