237₈ = 2∙8²+3∙8¹+7∙8⁰ = 128+24+7 = 159₁₀
1A1₁₆ = 1∙16²+10∙16¹+1∙16⁰ = 256+160+1 = 417₁₀
101₂ = 1∙2²+0∙2¹+1∙2⁰ = 4+0+1 = 5₁₀
159+417+5=581
ответ: 581
237₈ = 2∙8²+3∙8¹+7∙8⁰ = 128+24+7 = 159₁₀
1A1₁₆ = 1∙16²+10∙16¹+1∙16⁰ = 256+160+1 = 417₁₀
101₂ = 1∙2²+0∙2¹+1∙2⁰ = 4+0+1 = 5₁₀
159+417+5=581
ответ: 581