Дан фрагмент программы: a : =10; b : =a+1 : a : =b-a; write (a,b) какие числа будут выведены на экран компьютера?

Программа:

Pascal:

№2)

var

 m: array[1..10] of integer;

begin

 m[1]:=4; m[2]:=8; m[3]:=7; m[4]:=2; m[5]:=1; m[6]:=8; m[7]:=1; m[8]:=5; m[9]:=6; m[10]:=8;

 for var i := 1 to 10 do

   if m[i] = m.max then m[i]:= 0;

 writeln(m);

end.

№3)

const n = 10;

var

 a: array[1..n] of integer;

 i, k, tmp: integer;

begin

 for i := 1 to n do a[i] := random(0, 1);

 writeln('Массив: ', a);

 for i := 1 to n - 1 do

   for k := 1 to n - i do

     if a[k] > a[k + 1] then begin

       tmp := a[k];

       a[k] := a[k + 1];

       a[k + 1] := tmp;

     end;

 writeln(a);

end.

№5)

const n = 10;

var

 a: array[1..n] of integer;

 a1, a2: array[1..n div 2] of integer;

 i, k, tmp: integer;

begin

 for i := 1 to n do a[i] := random(-10, 10);

 writeln('Исходный массив: ',a);

 for i := 1 to n div 2 do a1[i] := a[i];

 for i := (n div 2 + 1) to n do a2[i - n div 2] := a[i];

 for i := 1 to n div 2 - 1 do

   for k := 1 to n div 2 - i do

     if a1[k] > a1[k + 1] then begin

       tmp := a1[k];

       a1[k] := a1[k + 1];

       a1[k + 1] := tmp;

     end;

 for i := 1 to n div 2 - 1 do

   for k := 1 to n div 2 - i do

     if a2[k] < a2[k + 1] then begin

       tmp := a2[k];

       a2[k] := a2[k + 1];

       a2[k + 1] := tmp;

     end;

 for i := 1 to n do

   if i <= 5 then a[i] := a1[i]

   else a[i] := a2[i - n div 2];

 writeln('Выходной массив: ', a);

end.

1)

a = int(input())

b = int(input())

for i in range(a, b+1):

   if i % ... == 0 and i % ... != 0:

       ...

print(...)

2)

a = int(input())

x = a*2

n = 0

while a < x:

   a = a + (a * 0.1)

   n += 1

print(n/4)

3)

sum = 0

for i in range(100):

   a = int(input())

   if a < 0 and a % 2 != 0:

       sum += a

print(a)

4)

a = input()

if a.count('0') != 0:

   print('est`')

else:

   print('net')

5)

p = int(input())

n = int(input())

c = 0

for i in range(n):

   a = int(input())

   if a > p:

       c += 1

print(c)

6)

n = int(input())

c = 0

for i in range(n):

   a = int(input())

   if a % 10 == 5:

       c += 1

print(c)

7)

a = int(input())

b = int(input())

n = int(input())

c = 0

for i in range(n):

   x = int(input())

   if a <= x <= b:

       c += 1

print(c)

8)

n = int(input())

c = 0

sum = 0

for i in range(n):

   x = float(input())

   if x > 10:

       sum += x

       c += 1

print(x / c)

9)

c = 0

while True:

   a = int(input())

   if a == 0:

       break

   if a % 2 == 0:

       c += 1

print(c)

10)

n = int(input())

c = 0

sum = 0

for i in range(n):

   x = float(input())

   if x < 10:

       sum += x

       c += 1

print(x / c)

11)

n = int(input())

c = 0

for i in range(n):

   x = int(input())

   if x % 10 == 3:

       c += 1

print(c)

12)

x = input()

if x.count('4') != 0:

   print('yes')

else:

   print('no')