Как называется свойство базы данных, которое означает, что БД содержит полную и непротиворечивую информацию и удовлетворяет всем заданным ограничениям?
Program esep; var input,output:text; n,i,j,g,nm,ans,t:integer; ara:array[0..1000] of integer; ar,arq:array[0..1000] of integer; ts,sum,a:integer; begin assign(input,'f.in'); reset(input); assign(output,'f.out'); rewrite(output); readln(input,a,n); ans:=10000; for i:=1 to n do begin read (input,ar[i]);ts:=ts+2*ar[i]; end; if ts<a then writeln(output,'no') else begin ara[1]:=3; for i:=2 to 15 do begin ara[i]:=3*ara[i-1]; end; for i:=1 to ara[n] do begin if arq[n]<2 then begin inc(arq[n]); sum:=sum+ar[n]; inc(nm); end else begin g:=n;while arq[g]>1 do begin sum:=sum-ar[g]*arq[g]; dec(nm,arq[g]);arq[g]:=0; dec(g); end; inc(arq[g]); sum:=sum+ar[g]; inc(nm); end; if sum=a then begin if nm<ans then ans:=nm; end; end; if ans>1000 then writeln(output,'yes') else writeln(output, ans); end; close(output); close(input); end.
Var input,output:text; n,i,j,g,nm,ans,t:integer;ara:array[0..1000] of integer;ar,arq:array[0..1000] of integer; ts,sum,a:integer;beginassign(input,'f.in');reset(input); assign(output,'f.out');rewrite(output);readln(input,a,n);ans:=10000; for i:=1 to n do beginread(input,ar[i]);ts:=ts+2*ar[i];end; if ts<a then writeln(output,'-1') else begin
ara[1]:=3;for i:=2 to 15 do begin ara[i]:=3*ara[i-1];end; for i:=1 to ara[n] do begin if arq[n]<2 then begin inc(arq[n]);sum:=sum+ar[n];inc(nm); end else begin g:=n;while arq[g]>1 do begin sum:=sum-ar[g]*arq[g];dec(nm,arq[g]);arq[g]:=0;dec(g);end; inc(arq[g]);sum:=sum+ar[g];inc(nm);end;if sum=a then begin if nm<ans then ans:=nm;end;end; if ans>1000 then writeln(output,'0') else writeln(output,ans); end; close(output);close(input);end.
var input,output:text;
n,i,j,g,nm,ans,t:integer;
ara:array[0..1000] of integer;
ar,arq:array[0..1000] of integer;
ts,sum,a:integer;
begin assign(input,'f.in');
reset(input);
assign(output,'f.out');
rewrite(output);
readln(input,a,n);
ans:=10000;
for i:=1 to n do begin read (input,ar[i]);ts:=ts+2*ar[i];
end;
if ts<a then writeln(output,'no') else
begin
ara[1]:=3;
for i:=2 to 15 do
begin
ara[i]:=3*ara[i-1];
end;
for i:=1 to ara[n] do
begin
if arq[n]<2 then
begin
inc(arq[n]);
sum:=sum+ar[n];
inc(nm);
end else begin
g:=n;while arq[g]>1 do
begin sum:=sum-ar[g]*arq[g];
dec(nm,arq[g]);arq[g]:=0;
dec(g);
end;
inc(arq[g]);
sum:=sum+ar[g];
inc(nm);
end;
if sum=a then begin
if nm<ans then ans:=nm;
end;
end;
if ans>1000 then writeln(output,'yes') else
writeln(output, ans);
end;
close(output);
close(input);
end.
for i:=1 to n do beginread(input,ar[i]);ts:=ts+2*ar[i];end;
if ts<a then writeln(output,'-1') else
begin
ara[1]:=3;for i:=2 to 15 do begin ara[i]:=3*ara[i-1];end;
for i:=1 to ara[n] do begin if arq[n]<2 then begin inc(arq[n]);sum:=sum+ar[n];inc(nm); end else begin g:=n;while arq[g]>1 do begin sum:=sum-ar[g]*arq[g];dec(nm,arq[g]);arq[g]:=0;dec(g);end;
inc(arq[g]);sum:=sum+ar[g];inc(nm);end;if sum=a then begin if nm<ans then ans:=nm;end;end;
if ans>1000 then writeln(output,'0') else writeln(output,ans); end;
close(output);close(input);end.