Найти сумму значений функции Y=COS(X/A)+X/(A-2) для X, изменяющегося от -20 до 3 с шагом 1,4. Результат вывести на экран и записать в файл.

1)
var
  i, j: integer;
  ar: array[1..6, 1..6]of integer;
 begin
  for i := 1 to 6 do
    for j := 1 to 6 do read(ar[i, j]);
  writeln;
  for i := 1 to 6 do swap(ar[i, 1], ar[i, 6]);
  for i := 1 to 6 do swap(ar[i, 2], ar[i, 5]);
  for i := 1 to 6 do swap(ar[i, 3], ar[i, 4]);
  for i := 1 to 6 do begin
    for j := 1 to 6 do write(ar[i, j], ' ');
    writeln;
  end;
end.
2)
var
  mr, rm: array [1..6, 1..6] of integer;
  i, j: integer;
 begin
  for i := 1 to 6 do
      for j := 1 to 6 do read(mr[i, j] );
  for i := 1 To 6 do
    for j := 1 To 6 do
      rm[i, j] := mr[j, i];
  writeLn;
  for i := 1 to 6 do
  begin
    for j := 1 to 6 do write(rm[i, j],' ');
    writeln;
   end;
  readln;
end.

{1}

const
 n = 6;
var
 a:array[1..n,1..n] of integer;
 i,j:integer;
 t:integer;

begin
 for i := 1 to n do
 for j := 1 to n do
  read(a[i,j]);
 
 for j := 1 to n div 2 do
 for i := 1 to n do
  begin
  t := a[i,j];
  a[i,j] := a[i,n+1-j];
  a[i,n+1-j] := t;
  end;
 
 for i := 1 to n do
  begin
  writeln;
  for j := 1 to n do
    write(a[i,j],' ');
  end
end.

{2}

const
 n = 6;
var
 a:array[1..n,1..n] of integer;
 i,j:integer;
 t:integer;

begin
 for i := 1 to n do
 for j := 1 to n do
  read(a[i,j]);
 
 for i := 1 to n do
 for j := i+1 to n do
  begin
  t := a[i,j];
  a[i,j] := a[j,i];
  a[j,i] := t;
  end;
 
 for i := 1 to n do
  begin
  writeln;
  for j := 1 to n do
    write(a[i,j],' ');
  end
end.