123_n = 93_(n+2)
1*n^2 +2*n^1 +3*n^0 = 9*(n+2)^1 + 3*(n+2)^0
n^2 +2n +3 = 9n+18 +3
n^2 +2n -9n -18 = 0
n^2 -7n -18 = 0
d = 49 +18*4 = 121
n = (7-11)/2 = -2
n = (7+11)/2 = 9
ответ: 9.
123_n = 93_(n+2)
1*n^2 +2*n^1 +3*n^0 = 9*(n+2)^1 + 3*(n+2)^0
n^2 +2n +3 = 9n+18 +3
n^2 +2n -9n -18 = 0
n^2 -7n -18 = 0
d = 49 +18*4 = 121
n = (7-11)/2 = -2
n = (7+11)/2 = 9
ответ: 9.