x
2
+
y
=
16
...
.
(
1
)
x + y = 4 (2)
rearrange (2) to y = 4 - x (could do x = 4 - y )
substitute y = 4 - x into (1)
hence:
4
−
⇒
8
and
0
factor and solve : 2x(x - 4 ) = 0
,
substitute these values into y = 4 - x , to find corresponding values of y.
x = 0 : y = 4 - 0 = 4 → (0 , 4)
x = 4 : y = 4 - 4 = 0 → (4 , 0 )
These are the points of intersection with the line x +y = 4 and the circle
Answer link
Объяснение:
x
2
+
y
2
=
16
...
...
...
...
...
...
.
.
(
1
)
x + y = 4 (2)
rearrange (2) to y = 4 - x (could do x = 4 - y )
substitute y = 4 - x into (1)
hence:
x
2
+
(
4
−
x
)
2
=
16
⇒
x
2
+
16
−
8
x
+
x
2
=
16
and
2
x
2
−
8
x
+
16
−
16
=
0
⇒
2
x
2
−
8
x
=
0
factor and solve : 2x(x - 4 ) = 0
⇒
x
=
0
,
x
=
4
substitute these values into y = 4 - x , to find corresponding values of y.
x = 0 : y = 4 - 0 = 4 → (0 , 4)
x = 4 : y = 4 - 4 = 0 → (4 , 0 )
These are the points of intersection with the line x +y = 4 and the circle
x
2
+
y
2
=
16
Answer link
Объяснение:
using namespace std;
void countChars() {
char s[256];
cout << "Введите строку: ";
cin.getline(s, 256);
int count = 0;
for (unsigned int i = 0; i < strlen(s); i++)
count++;
cout << "Количество символов в строке: " << count << endl;
}
int main() {
setlocale(LC_ALL, "Russian");
countChars();
system("pause");
return 0;
}
//
// или так
//
#include <iostream>
using namespace std;
int countChars(char* s) {
int count = 0;
for (unsigned int i = 0; i < strlen(s); i++)
count++;
return count;
}
int main() {
setlocale(LC_ALL, "Russian");
char s[256];
cout << "Введите строку: ";
cin.getline(s, 256);
cout << "Количество символов в строке: " << countChars(s) << endl;
system("pause");
return 0;
}