1)
M(BaF2) = 137 + 19*2 = 175 g/mol
M(Fe2(SO3)3) = 56*2 + (32+16*3)*3 = 352 g/mol
M(K2CO3) = 39*2+12+16*3 = 138 g/mol
2)
дано
n(Na3PO4) = 10 mol
m(Na3PO4) - ?
M(Na3PO4) = 164 g/mol
m(Na3PO4) = n*m = 10*164 = 1640 g
ответ 1640 гр
3)
m(H2S) = 0.5 g
V(H2S) = ?
M(H2S) = 34 g/mol
Vm = 22,4 l/mol
V(H2S) = Vm * m(H2S) / M(H2S) = 22.4 * 0.5 / 34 = 0.33 L
ответ 0.33 л
Объяснение:
1)
M(BaF2) = 137 + 19*2 = 175 g/mol
M(Fe2(SO3)3) = 56*2 + (32+16*3)*3 = 352 g/mol
M(K2CO3) = 39*2+12+16*3 = 138 g/mol
2)
дано
n(Na3PO4) = 10 mol
m(Na3PO4) - ?
M(Na3PO4) = 164 g/mol
m(Na3PO4) = n*m = 10*164 = 1640 g
ответ 1640 гр
3)
дано
m(H2S) = 0.5 g
V(H2S) = ?
M(H2S) = 34 g/mol
Vm = 22,4 l/mol
V(H2S) = Vm * m(H2S) / M(H2S) = 22.4 * 0.5 / 34 = 0.33 L
ответ 0.33 л
Объяснение: