3H2SO4+Fe2O3=Fe2(SO4)3+6H2O
n(H2SO4)=49/98=0,5моль
n(Fe2(SO4)3)=x=0,5/3=0,167моль
m(Fe2(SO4)3)=0,167*(192+112+96)=0,167*400=66,8г
3H2SO4+Fe2O3=Fe2(SO4)3+6H2O
n(H2SO4)=49/98=0,5моль
n(Fe2(SO4)3)=x=0,5/3=0,167моль
m(Fe2(SO4)3)=0,167*(192+112+96)=0,167*400=66,8г