2CH4=C2H2+3H2;V(H2)=(1*3):2=1,5л;
H2+Cl2=2HCl; V(HCl)=1,5*2=3л;m(HCl)=(3:22,4)*36,5=4,89г;
W(HCl)=4,89:(20+4,89)=0,1965(19,65%)
2CH4=C2H2+3H2;V(H2)=(1*3):2=1,5л;
H2+Cl2=2HCl; V(HCl)=1,5*2=3л;m(HCl)=(3:22,4)*36,5=4,89г;
W(HCl)=4,89:(20+4,89)=0,1965(19,65%)